I am looking to produce multiple lists based on the same function which randomises data based on a list. I want to be able to easily change how many of these new lists I want to have and then combine. The code which creates each list is the following:
"""
"""
R_ensemble=[]
for i in range(0,len(R)):
if R[i]==0:
R_ensemble.append(0)
else:
R_ensemble.append(np.random.normal(loc=R[i],scale=R[i]/4,size=None))
return R_ensemble
This perturbs each value from the list based on a normal distribution.
To combine them is fine when I just want a handful of lists:
"""
"""
ensemble_form_1,ensemble_form_2,ensemble_form_3 = [],[],[]
ensemble_form_1 = normal_transform(R)
ensemble_form_2 = normal_transform(R)
ensemble_form_3 = normal_transform(R)
zipped_ensemble = list(zip(ensemble_form_1,ensemble_form_2,ensemble_form_3))
df_ensemble = pd.DataFrame(zipped_ensemble, columns = ['Ensemble_1', 'Ensemble_2','Ensemble_3'])
return ensemble_form_1, ensemble_form_2, ensemble_form_3
How could I repeat the same randomisation process to create a fixed number of lists (say 50 or 100), and then combine them into a table? Is there an easy way to do this with a for loop, or any other method? I'd need to be able to pick out each new list/column individually, as I would be combining the results in some way.
Any help would be greatly appreciated.
You can construct multiple lists and a table like this:
import pandas as pd
import numpy as np
# Your function for creating the individual lists
def normal_transform(R):
R_ensemble=[]
for i in range(0,len(R)):
if R[i]==0:
R_ensemble.append(0)
else:
R_ensemble.append(np.random.normal(loc=R[i],scale=R[i]/4,size=None))
return R_ensemble
# Construction of multiple lists and the dataframe
NUM_LISTS = 50
R = list(range(100))
data = dict()
for i in range(NUM_LISTS):
data['Ensemble_' + str(i)] = normal_transform(R)
df_ensemble = pd.DataFrame(data)
You can access the individual lists/ columns like this:
df_ensemble['Ensemble_42']
df_ensemble[df_ensemble.columns[42]]