Concatenating string outputs of a for loop in Python 3

Question

I have a code which, after a nested for loop, provides me with a unique string in each iteration. I want to find a way to concatenate those outputs so that my final line is a single string of those unique strings. Ignoring how ugly and inefficient this code is, what steps can I take to achieve the desired result?

VOWELS = ('a','e','i','o','u','A','E','I','O','U')

ad = "Desirable unfurnished flat in quiet residential area"
# remove all vowels, unless the word starts with a vowel

def is_vowel(c):
    return c in VOWELS

def mod3(ad):
    testAd =ad.split()
    for word in testAd:
        modAd = ""
        i = 0
        for char in word:
            if i == 0:
                modAd += char
            elif not is_vowel(char):
                modAd += char
            i+=1
        print(modAd)

mod3(ad)

my output for this code:

Otherwise, when I modify my code to look like this:

But my output is:

I don't believe a .join() would work here as it's not a list type. And I can't figure out where to put a string concat + anywhere without my for loop going bonkers. Any advice?

Answer 1

You can create a string result where you can concatenate your each iteration result and print that. You need to add spaces after each addition of words. So, append + " " to your result variable as well.

def mod3(ad):
    result = ""
    testAd =ad.split()
    for word in testAd:
        modAd = ""
        i = 0
        for char in word:
            if i == 0:
                modAd += char
            elif not is_vowel(char):
                modAd += char
            i+=1
        result += modAd + " "
    print(result)

Second option: This is my take on it:

def mod4(ad):
    result = ""
    testAd =ad.split()
    for word in testAd:
          for i, char in enumerate(word):
              if i == 0:
                  result += char
              if i > 0 and char not in VOWELS:
                  result += char
          result += " "
    print(result)