apple.yml
apple.md
orange.yml
orange.md
I have files as .md and .yml I would like to concat them into one .md file if the filename match
What would be the next step here?
contents = {}
file_extension1 = "yml"
file_extension2 = "md"
# Get all files and directories that are in current working directory
for file_name in os.listdir('folder/'):
# print(file_name)
# Use '.' so it doesn't match directories
if file_name.endswith(('.' + file_extension1 , '.'+ file_extension2)):
print(file_name)
Here is how you can use the glob module:
from glob import glob
for f1 in glob("*.yml"): # For every yml file in the current folder
for f2 in glob("*.md"): # For every md file in the current folder
if f1.rsplit('.')[0] == f2.rsplit('.')[0]: # If the names match
with open(f1, 'r') as r1, open(f2, 'r') as r2: # Open each file in read mode
with open(f"{new}_f2", 'w') as w: # Create a new md file
w.write(r1.read()) # Write the contents of the yml file into it
w.write('\n') # Add a newline
w.write(r2.read()) # Write the contents of the md file into it
That code is for when there are inconsistent yml and md files. If all the yml files have a corresponding md file, and they are in a folder with other interfering yml and md files, you can:
from glob import glob
m = sorted(glob("*.md"))
y = sorted(glob("*.yml"))
for f1, f2 in zip(m, y):
with open(f1, 'r') as r1, open(f2, 'r') as r2:
with open(f"new_{f1}", 'w') as w:
w.write(f1.read())
w.write('\n')
w.write(f2.read())
UPDATE:
To address the comment below:
from os import listdir
files = listdir()
for f in files: # For every yml file in the current folder
if f.endswith('.yml') and f.rsplit('.')[1]+'.md' in files:
with open(f1, 'r') as r1, open(f.rsplit('.')[1]+'.md', 'r') as r2: # Open each file in read mode
with open(f"{new}_f2", 'w') as w: # Create a new md file
w.write(r1.read()) # Write the contents of the yml file into it
w.write('\n') # Add a newline
w.write(r2.read()) # Write the contents of the md file into it