using awk to cut a specific part

Question

i am dealing many lines containing paths example :

posterita/posterita/web/jsp/pos/posReport1.jsp
build/web/view.jsp
uPortal-webapp/src/main/webapp/WEB-INF/flows/user-manager/selectUserAction.jsp
config/auth.php
database/seeds/DatabaseSeeder.php
admin/modules/announcement/functions.inc.php

what i need to do using bash print the first directory I want the output to be like

posterita
build
uPortal-webapp
config
database
admin

the same method with second and third directory

posterita
web
src
seeds
modules

How can i use awk , sed or cut to do this ?

Answer 1

$ awk -F'/' -v n=1 'NF>n{print $n}' file
posterita
build
uPortal-webapp
config
database
admin

$ awk -F'/' -v n=2 'NF>n{print $n}' file
posterita
web
src
seeds
modules