I have the following method from my controller that gets the data from the site:
$goutteClient = new Client();
$guzzleClient = new GuzzleClient([
'timeout' => 60,
]);
$goutteClient->setClient($guzzleClient);
$crawler = $goutteClient->request('GET', 'https://html.duckduckgo.com/html/?q=Laravel');
$crawler->filter('.result__title .result__a')->each(function ($node) {
dump($node->text());
});
The above code gives me the title of contents from the search results. I also want to get the link of the corresponding search result. That resides in class result__extras__url
.
How do I filter the link in and the title at once? Or do I have to run another method for that?
Try to inspect the attributes of the nodes. Once you get the href
attribute, parse it to get the URL.
$crawler->filter('.result__title .result__a')->each(function ($node) {
$parts = parse_url(urldecode($node->attr('href')));
parse_str($parts['query'], $params);
$url = $params['uddg']; // DDG puts their masked URL and places the actual URL as a query param.
$title = $node->text();
});