I have a df. If 'info' appears in a row, I would like a function to take the column-name and and paste it together with the information from the cell with a '=' between them. I have tried the function below, which works, except that it does not refer to the columnname from the right column
df <- data.frame('criteria1' = c('info','1', 'info', '', 'info'), "criteria2" = c('y','3', '', 'info', ''), "criteria3" = c('y','7', '', 'info', 'info'))
df[] <- sapply(df, function(x) ifelse(x == 'info', paste(colnames(df)[x], ' = ', x),''))
My expected output is something like this (it does not matter if the columnnames are deleted, it is just the info from the cells that are important)
df_exp <- data.frame('criteria1' = c('criteria1= info','', 'criteria1=info', '', 'criteria1 =info'), "criteria2" = c('','', '', 'criteria2 = info', ''), "criteria3" = c('','', '', 'criteria3 = info', 'criteria3 = info'))
I'd go for the column numbers, either 1:ncol(df) (which is faster) or seq(df). I use the former.
df <- sapply(1:ncol(df), function(x)
ifelse(df[[x]] == 'info', paste(colnames(df)[x], ' = ', df[[x]]),''))
df
# [,1] [,2] [,3]
# [1,] "criteria1 = info" "" ""
# [2,] "" "" ""
# [3,] "criteria1 = info" "" ""
# [4,] "" "criteria2 = info" "criteria3 = info"
# [5,] "criteria1 = info" "" "criteria3 = info"
Another nice way using stack/unstack:
r <- grep("info", tmp$values)
tmp <- stack(df)
tmp[r, 1] <- apply(tmp[r, 2:1], 1, paste, collapse="=")
tmp[-r, 1] <- "" ## in case you want non-"info" cells cleared
df <- unstack(tmp)
df
# criteria1 criteria2 criteria3
# 1 criteria1=info
# 2
# 3 criteria1=info
# 4 criteria2=info criteria3=info
# 5 criteria1=info criteria3=info