How i can echo only the header that i want? php

Question

So i want to echo only a header not all of them.

An example the Server header which contains the information what server it is.

Or X-powered: PHP/version header.

I know i can use print_r($headers["0"]); but the problem here is i will don't know what number is that header exactly.

Array ( [0] => HTTP/1.1 403 Forbidden [1] => Date: Fri, 26 Jun 2020 21:44:53 GMT [2] => Content-Type: text/html; charset=UTF-8 [3] => Connection: close [4] => CF-Chl-Bypass: 1 [5] => Set-Cookie: __cfduid=d3cb45768070a21a77835f417592827541593207893; expires=Sun, 26-Jul-20 21:44:53 GMT; path=/; domain=.onetap.com; HttpOnly; SameSite=Lax...................

how i can print only the header i want without knowing the array number.

$url = "https://www.google.com/";
$headers = get_header($url);

print_r($headers["0"]);

Answer 1

Iterate over your $headers and search for a substring in every header:

$headers = get_headers($url);
foreach ($headers as $header) {
    if (false !== strpos($header, 'X-powered:')) {
        echo $header;
        // now extract required value, e.g:
        $data = explode('/', $header);
        echo 'Version is: ' . $data[1];
        
        // use break to stop further looping
        break;
    }
}

Using second parameter of get_headers as 1, will even give you an array, so you can check if required key exists with isset or array_key_exists:

$headers = get_headers($url);
if (isset($headers['X-powered'])) {
    echo $headers['X-powered'];
    // now extract required value, e.g:
    $data = explode('/', $headers['X-powered']);
    echo 'Version is: ' . $data[1];
}