I picked up from an old post here that it is not possible to print the results of an itertools.permutations except by converting to a list first. This is what I did here:
import itertools
p = itertools.permutations('ABCD', 2)
print(list(p))
I get the following output (in Jupyter Notebook):
[('A', 'B'), ('A', 'C'), ('A', 'D'), ('B', 'A'), ('B', 'C'), ('B', 'D'), ('C', 'A'), ('C', 'B'), ('C', 'D'), ('D', 'A'), ('D', 'B'), ('D', 'C')]
I picked up the original example from itertools from docs.python.org. The example section on that page shows the output as:
AB AC AD BA BC BD CA CB CD DA DB DC
That same page doesn't actually explain how to use itertools, having to import the module or how to get the output, so do I take it also that although it shows that output in a conveniently readable format, it was not produced in code but just typeset this way?
Either way, is there a way to tweak that print command to produce the same format as above?
Thank you for your comments and suggestions.
All the best. c
Here is what you can do:
import itertools
p = itertools.permutations('ABCD', 2)
print(' '.join([a+b for a,b in p]))
Output:
AB AC AD BA BC BD CA CB CD DA DB DC