Show the current variable IFS
:
echo $IFS |xxd
00000000: 0a
I want to reset IFS
as default value \t\n
.
IFS=$' \t\n'
echo $IFS |xxd
00000000: 0a
Why can't reset IFS variable?
You are resetting IFS
correctly. The problem is in your echo
. You should use echo -n "$IFS" | xxd
.
Taking a look at man bash
(emphasis mine):
Word Splitting
The shell scans the results of parameter expansion, command substitution, and arithmetic expansion that did not occur within double quotes for word splitting.
The shell treats each character of
IFS
as a delimiter, and splits the results of the other expansions into words on these characters. IfIFS
is unset, or its value is exactly<space><tab><newline>
, the default, then sequences of<space>
,<tab>
, and<newline>
at the beginning and end of the results of the previous expansions are ignored, and any sequence ofIFS
characters not at the beginning or end serves to delimit words. IfIFS
has a value other than the default, then sequences of the whitespace charactersspace
andtab
are ignored at the beginning and end of the word, as long as the whitespace character is in the value ofIFS
(anIFS
whitespace character). Any character inIFS
that is notIFS
whitespace, along with any adjacentIFS
whitespace characters, delimits a field. A sequence ofIFS
whitespace characters is also treated as a delimiter. If the value ofIFS
is null, no word splitting occurs.
Since you did not double-quote IFS
, it goes through the shell's word-splitting logic. Since IFS
by definition contains the IFS
characters within itself, they are ignored by the shell. Double-quoting prevents this.