I am working on a django web application. Here the web app generates a pandas dataframe when a form is submitted. This dataframe is stored in the root directory. I have another view that is used for downloading the generated csv file. But when I redirect to the download page, I get a No reverse match error.
this is my code so far
def randomfilename(stringLength=8):
lettersAndDigits = string.ascii_letters + string.digits
return ''.join(random.choice(lettersAndDigits) for i in range(stringLength))
def generate_dataframe(request):
if request.method == 'POST':
...
df = pd.DataFrame(columns=cols)
df['title'] = title_lst
df['link'] = product_links[:1]
fn = randomfilename()
df.to_csv('./'+fn+'.csv')
return redirect("download_file", filename = fn)
def download_file(request, filename):
if request.method == 'POST':
file_path = './'+filename
file = open(file_path, 'r')
mime_type, _ = mimetypes.guess_type(file_path)
response = HttpResponse(file, content_type=mime_type)
response['Content-Disposition'] = "attachment; filename=%s" % filename
return response
project urls.py
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('scraper.urls')),
]
scraper urls.py
urlpatterns = [
path('generate', views.generate_dataframe, name='generate_dataframe'),
path('download/<filename>/', views.download_file, name='download_file'),
]
I know I am messing up the URL somewhere. But I am not sure how to rectify this problem. Please help me. Thanks in advance.
Try this:
In your views
from django.urls import reverse
def generate_dataframe(request):
...
return redirect(reverse('download_file', kwargs={'filename': fn}))
In your urls.py:
urlpatterns = [
...
path('download/<str:filename>/', views.download_file, name='download_file'),
]
In your template:
{% url 'download_file' filename %}