I have a dataset that looks like this:
Month count
2009-01 12
2009-02 310
2009-03 2379
2009-04 234
2009-05 14
2009-08 1
2009-09 34
2009-10 2386
I want to plot the data (months as x values and counts as y values). Since there are gaps in the data, I want to convert the Information for the Month into a date. I tried:
as.Date("2009-03", "%Y-%m")
But it did not work. Whats wrong? It seems that as.Date()
requires also a day and is not able to set a standard value for the day? Which function solves my problem?
Try this. (Here we use text=Lines
to keep the example self contained but in reality we would replace it with the file name.)
Lines <- "2009-01 12
2009-02 310
2009-03 2379
2009-04 234
2009-05 14
2009-08 1
2009-09 34
2009-10 2386"
library(zoo)
z <- read.zoo(text = Lines, FUN = as.yearmon)
plot(z)
The X axis is not so pretty with this data but if you have more data in reality it might be ok or you can use the code for a fancy X axis shown in the examples section of ?plot.zoo
.
The zoo series, z
, that is created above has a "yearmon"
time index and looks like this:
> z
Jan 2009 Feb 2009 Mar 2009 Apr 2009 May 2009 Aug 2009 Sep 2009 Oct 2009
12 310 2379 234 14 1 34 2386
"yearmon"
can be used alone as well:
> as.yearmon("2000-03")
[1] "Mar 2000"
Note:
"yearmon"
class objects sort in calendar order.
This will plot the monthly points at equally spaced intervals which is likely what is wanted; however, if it were desired to plot the points at unequally spaced intervals spaced in proportion to the number of days in each month then convert the index of z
to "Date"
class: time(z) <- as.Date(time(z))
.