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dictionarystructinitializationoctave

Octave: concise way of creating and initializing a struct

I have a cell array of strings of length 3

headers_ca =
{
  [1,1] = time
  [1,2] = x
  [1,3] = y
}

I want to create a struct that mimics a python dict, with the values in headers_ca as keys (fieldnames in Octave) and an initializer value ival for all entries. It would be a struct, since even dict exists in octave, it has been deprecated.

I could do (brute force) s = struct("time", ival, "x", ival, "y", ival);

What is the most concise way to do this?

I know I can do a for loop. Can it be avoided?

I would be working with much longer cell arrays.

Solution

  • You can use struct or cell2struct to create the structure.

    headers_ca = {'time','x','y'};
headers_ca(2, :) = {ival};
s = struct(headers_ca{:});

headers_ca = {'time','x','y'};
ivals = repmat({ival}, numel(headers_ca), 1);
s = cell2struct(ivals, headers_ca);