Django: How to generate unique order id

Question

This is how my model looks like. When ever user orders. The order id provided by django is simple. Its like 1,2,3 ..... 100.

class UserOrder(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL, related_name='orders', 
           on_delete=models.CASCADE)
    cart = models.ForeignKey(Cart, related_name="orders", on_delete=models.CASCADE, null=True, 
           blank=True)
    date = models.DateTimeField(default=datetime.now)
    total_price = models.IntegerField(null=True, blank=True)
    note = models.TextField(null=True, blank=True)
    cancel_reason = models.TextField(null=True, blank=True)
    cancelled = models.BooleanField(default=False)
    confirmed = models.BooleanField(default=False)

    def __str__(self):
        return self.user.username 

Answer 1

Your question is not well defined but I think I understand your problem, you need a id (lookup field) that is not simple.

you can use uuid, and use this uuid for all the lookup in the viewsets, instead of the sequentially created id by django. something like this lookup_field = 'uuid' in views.

import uuid

class UserOrder(models.Model):
     uuid = models.UUIDField(default=uuid.uuid4, unique=True, db_index=True, editable=False)

read more about uuids here https://docs.python.org/3/library/uuid.html#uuid.uuid4