How to redirect to another page from def form_valid(self):
inside a generic FormView
.
I know I should do something like Super(className, self).form_valid(form):
but this will never redirect to a dynamic link, but will only go to the success URL
Here is my code :
class ProductCreateView(FormView):
form_class = ProductCreateForm
template_name = 'back_office/product_create_form.html'
success_url = reverse_lazy('product_recipe_wrapper')
def form_valid(self, form):
category = Category.objects.get(id=self.kwargs['pk'])
name = form.cleaned_data['name']
image = form.cleaned_data['image']
big_size = form.cleaned_data['big_size']
mid_size = form.cleaned_data['mid_size']
small_size = form.cleaned_data['small_size']
new_product = Product.objects.create(category=category, name=name, image=image)
big_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=1),
sell_price=big_size)
mid_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=2),
sell_price=mid_size)
small_size_object = ProductSize.objects.create(product=new_product, size=Size.objects.get(id=3),
sell_price=small_size)
if small_size_object.sell_price != 0:
return reverse_lazy('product_small_recipe', args=[small_size_object.id])
def get_context_data(self, *args, **kwargs):
context = super(ProductCreateView, self).get_context_data()
context['category'] = Category.objects.get(id=self.kwargs['pk'])
return context
The form_valid
method needs to return a response. The error message It returned None instead means that the method didn't return anything at all. In the code above, that would happen when small_size_object.sell_price == 0:
.
Next, you can't do return reverse_lazy(...)
, because the method needs to return a response, not a URL. If you want to redirect, you can use HttpResponseRedirect
, for example:
from django.http import HttpResponseRedirect
class ProductCreateView(FormView):
...
def form_valid(self, form):
...
return HttpResponseRedirect(reverse('product_small_recipe', args=[small_size_object.id]))
Note you can use reverse
here instead of reverse_lazy
because you're inside a method.
You can simplify the code by using the redirect
shortcut.
from django.shortcuts import redirect
class ProductCreateView(FormView):
...
def form_valid(self, form):
...
return redirect('product_small_recipe', small_size_object.id)