Python script for word count execution

Question

I have a folder "A" and many files within it ( say 100 ). I want to open the all these files(all are text files) and count the number of times the word "virtual memory" is present in all of them [Either the total sum or the number of times present in each file] I tried something like this but not able to achieve the same.

path = 'MY_PATH'

count=0
filecount=0
files = []
# r=root, d=directories, f = files
for r, d, f in os.walk(path):
    for file in f:
        files.append(os.path.join(r, file))
        print(files)
        for fileList in files:
            with open(fileList, "r") as f:
                # text = f.read()
                # print(len(text))
                print('OPENING FILE: ',f)
                for word in f:
                    #print(word)
                    if(word == 'virtual memory'):
                        print('WORD FOUND')
                        count+=1

print("COUNT : ", count)

Is there any quick script which I could use to execute the above query or some corrections I need to make? Thanks in advance!

Answer 1

Use file.count to count the number of a phrase in a txt file. Here a simple implementation how you can do this:

import os
path = 'MY_PATH'
count= 0
for root, dirs, files in os.walk(path):
    for file in files:
        num=0
        with open(os.path.join(root, file),"r") as f:
            f_reader =f.read()
            team  = 'virtual memory'
            num = f_reader.count(team)
        count+=num
        print('OPENING FILE: ',file, ' - Count:', num)
print("COUNT : ", count)