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R: Substituting missing values (NAs) with two different values


I might be overcomplicating things - would love to know if if there is an easier way to solve this. I have a data frame (df) with 5654 observations - 1332 are foreign-born, and 4322 Canada-born subjects.

The variable df$YR_IMM captures: "In what year did you come to live in Canada?" See the following distribution of observations per immigration year table(df$YR_IMM) :

1920 1926 1928 1930 1939 1942 1944 1946 1947 1948 1949 1950 1951 1952 1953 1954 
2    1    1    2    1    2    1    1    1    9    5    1    7   13    3    5 
1955 1956 1957 1958 1959 1960 1961 1962 1963 1964 1965 1966 1967 1968 1969 1970 
10    5    8    6    6    1    5    1    6    3    7   16   18   12   15   13 
1971 1972 1973 1974 1975 1976 1977 1978 1979 1980 1981 1982 1983 1984 1985 1986 
10   17    8   18   25   16   15   12   16   27   13   16   11    9   17   16 
1987 1988 1989 1990 1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002 2003
24   21   31   36   26   30   26   24   22   30   29   26   47   52   53   28   9

Naturally these are only foreign-born individuals (mean = 1985) - however, 348 foreign-borns are missing. There are a total of 4670 NAs that also include Canada-borns subjects.

How can I code these df$YR_IMM NAs in such a way that

348 (NA) --> 1985
4322(NA) --> 100

Additionally, the status is given by df$Brthcoun with 0 = "born in Canada" and 1 = "born outside of Canada.

Hope this makes sense - thank you!

EDIT: This was the solution ->

df$YR_IMM[is.na(df$YR_IMM) & df$Brthcoun == 0] <- 100 df$YR_IMM[is.na(df$YR_IMM) & df$Brthcoun == 1] <- 1985


Solution

  • Try the below code:

    df$YR_IMM[is.na(df$YR_IMM) & df$Brthcoun == 0] <- 100
    df$YR_IMM[is.na(df$YR_IMM) & df$Brthcoun == 1] <- 1985
    

    I hope this helps!