URLLIB request code reading issue. Cannot read error code 404

Question

I am trying to read the url code using URLLIB. Here is my code:

import urllib

url = "https://www.facebook.com/fads0000fass"

r = urllib.request.urlopen(url)
p = r.code

if(p == "HTTP Error 404: Not Found" ):
        print("hello")
else:
        print("null")

The url I am using will show error code 404 but I am not able to read it. I also tried if(p == 404) but I get the same issue. I Can read other codes i.e. 200, 201 etc.

Can you please help me fix it?

traceback:

Traceback (most recent call last):
  File "gd.py", line 7, in <module>
    r = urllib.request.urlopen(url)
  File "/usr/lib64/python3.7/urllib/request.py", line 222, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib64/python3.7/urllib/request.py", line 531, in open
    response = meth(req, response)
  File "/usr/lib64/python3.7/urllib/request.py", line 641, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib64/python3.7/urllib/request.py", line 569, in error
    return self._call_chain(*args)
  File "/usr/lib64/python3.7/urllib/request.py", line 503, in _call_chain
    result = func(*args)
  File "/usr/lib64/python3.7/urllib/request.py", line 649, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 404: Not Found

Answer 1

I'm not sure that's what you're asking.

import urllib.request

url = "https://www.facebook.com/fads0000fass"

try:
    r = urllib.request.urlopen(url)
    p = r.code
except urllib.error.HTTPError:
    print("hello")