How to pass more than one parameter to url in django

Question

HTML page has 2 button to process payment, I need to pass 2 parameters to url for a reason. Below is the method I tried but it's not working. Can someone help me here..??

<a href="{% url 'process-payment' order.id button.id %}"   id = "CashOnDelivery" class="btn btn-warning"> Cash on Delivery</a> 
<a href="{% url 'process-payment' order.id button.id %}"  id = "Card" class="btn btn-warning">Pay through Card</a>

views.py

def process_payment(request, order_id, button_id):
    if id == CashOnDelivery
     # directly take order
    return redirect (reverse('update-records', kwargs={'order_id': order_id}))

    else 
     # process the card payment then update transaction 
    return redirect (reverse('update-records', kwargs={'order_id': order_id}))

urls.py

urlpatterns=[
 path('payment/<order_id>/<button_id>',views.process_payment, name='process-payment'),
]

Answer 1

This is because your variable is not defined.

<a href="{% url 'process-payment' order.id 'CashOnDelivery' %}" id = "CashOnDelivery" class="btn btn-warning"> Cash on Delivery</a>.

<a href="{% url 'process-payment' order.id 'Card' %}" id = "Card" class="btn btn-warning">Pay through Card</a>.

Also there seems you are not checking right id.

def process_payment(request, order_id, button_id):
    if button_id == CashOnDelivery
     # directly take order
    return redirect (reverse('update-records', kwargs={'order_id': order_id}))

    else 
     # process the card payment then update transaction 
    return redirect (reverse('update-records', kwargs={'order_id': order_id}))```