pythonstringdecimal# Easy way of finding decimal places

Is there an easy way or integrated function to find out the decimal places of a floating point number?

The number is parsed from a string, so one way is to count the digits after the `.`

sign, but that looks quite clumsy to me. Is there a possibility to get the information needed out of a `float`

or `Decimal`

object?

Solution

To repeat what others have said (because I had already typed it out!), I'm not even sure such a value would be meaningful in the case of a floating point number, because of the difference between the decimal and binary representation; often a number representable by a finite number of decimal digits will have only an infinite-digit representation in binary.

In the case of a `decimal.Decimal`

object, you can retrieve the exponent using the `as_tuple`

method, which returns a namedtuple with `sign`

, `digits`

, and `exponent`

attributes:

```
>>> d = decimal.Decimal('56.4325')
>>> d.as_tuple().exponent
-4
>>> d = decimal.Decimal('56.43256436')
>>> d.as_tuple().exponent
-8
>>> d = decimal.Decimal(str(56.4325))
>>> d.as_tuple().exponent
-4
```

The negation of the exponent is the number of digits after the decimal point, unless the exponent is greater than `0`

.

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