-- link removed --
How can I convert the numbers in the above website into stars using Jquery with a for loop to add however many stars, and a round up, round down function.
I prefer to round using this example:
You would need to update your list of ratings to be in a selectable container, and the rading would need to be encapsulated in it's own selector.
HTML:
<ul class="ratings">
<li>Overall Rating Data (no stars): <span>3.14285714286</span></li>
<li>Overall Grounds Data (no stars): <span>3.14285714286</span></li>
<li>Overall Price Data (no stars): <span>3.14285714286</span></li>
<li>Overall Staff Data (no stars): <span>3</span></li>
<li>Overall Maintenance Data (no stars): <span>2.85714285714</span></li>
<li>Overall Noise Data (no stars): <span>3.42857142857</span></li>
<li>Overall Amenities Data (no stars): <span>3.57142857143</span></li>
<li>Overall Location Data (no stars): <span>3.28571428571</span></li>
<li>Overall Parking Data (no stars): <span>3.28571428571</span></li>
<li>Overall Safety Data (no stars): <span>3</span></li>
</ul>
JS:
$(document).ready(function() {
$('ul.ratings li').each(function() {
var $el = $(this);
var rating = $el.find('span').text();
var $stars = $('<div><div class="ratings-stars"></div><div class="ratings-stars"></div><div class="ratings-stars"></div><div class="ratings-stars"></div><div class="ratings-stars"></div></div>');
var full_stars = Math.floor(rating);
var half_star = false;
var remainder = rating - full_stars;
if(remainder >= 0.25 && remainder <= 0.75) {
half_star = true;
} else if(remainder > 0.75) {
full_stars += 1;
}
$stars.find('div:lt('+full_stars+')').addClass('star');
if(half_star) {
$stars.find('div:eq('+full_stars+')').addClass('half-star');
}
$el.find('span').replaceWith($stars);
});
});
The CSS I'll leave up to you.
EDIT: Updated $stars
to use <div />
instead of <span />