Is ther a better way of getting the file name and the last x diretory names by using pathlib

Question

I have the path /bin/kk/bb/pp/hallo.png and want to get: pp/hallo.png. I checked https://docs.python.org/3/library/pathlib.html and found no direct way.

This is the way i use right now:

from pathlib import Path

a = Path("/bin/kk/bb/pp/hallo.png")

# get the parts i want 
b = list(a.parts[-2:])

# add / and join all together 
c = "".join([ "/" + x  for x in b])

d = Path(c)
d

Output:

PosixPath('/pp/hallo.png')

I'm not happy with this and searching for a better / cleaner way.

Maybe something like this:

a[-2:] -> PosixPath('/pp/hallo.png')

Answer 1

You can do it like so:

from pathlib import Path

a = Path("/path/to/some/file.txt")

b = Path(*a.parts[-2:])
# PosixPath('some/file.txt')

Alternatively as a function:

def last_n_parts(filepath: Path, n: int = 2) -> Path:
    return Path(*filepath.parts[-abs(n):])

---

The only reason I could think of that you'd need something like this is if you're specifying an output file that share the same directory structure. E.g. input is /bin/kk/bb/pp/hallo.png and output will be /other/dir/pp/hallo.png. In that case you can:

in_file = Path("/bin/kk/bb/pp/hallo.png")
out_dir = Path("/other/dir")

out_file = out_dir / last_n_parts(in_file)
# PosixPath('/other/dir/pp/hallo.png')