Ip address checker doesn't output IP address

Question

Following the code from here I have got an IP address checker. However instead of outputting an IP address it outputs []. Code:

import urllib.request
import re

print("we will try to open this url, in order to get IP Address")

url = "http://checkip.dyndns.org"

print(url)

request = urllib.request.urlopen(url).read()

theIP = re.findall(r"d{1,3}.d{1,3}.d{1,3}.d{1,3}", request.decode('utf-8'))


print("your IP Address is: ",  theIP)

Expected output:

we will try to open this url, in order to get IP Address
http://checkip.dyndns.org
your IP Address is: 40.74.89.185

The IP address there is not mine and comes from HERE.

Real output:

we will try to open this url, in order to get IP Address
http://checkip.dyndns.org
your IP Address is:  []

I have just copied from the website and then fixed the errors. What have I done wrong. Help please...

My python version is idle 3.8.

Answer 1

Turns out that your regex where wrong: I've updated the code and using requests get:

findall will return a list of elements since you are get only one ip back just use [0]

from requests import get
import re
iphtml = get('http://checkip.dyndns.org').text
theIP = re.findall( r'[0-9]+(?:\.[0-9]+){3}', iphtml)
print(f"Your IP is: {theIP[0]}")

Your code updated:

import urllib.request
import re

print("we will try to open this url, in order to get IP Address")

url = "http://checkip.dyndns.org"

print(url)

request = urllib.request.urlopen(url).read()

theIP = re.findall(r'[0-9]+(?:\.[0-9]+){3}', request.decode('utf-8'))


print("your IP Address is: ",  theIP[0])