Del list and next list element in list if string exist

Question

I have an example:

list = [['2 a', 'nnn', 'xxxx','last'], ['next, next'], ['3', '4', 'next']]

for i in range(len(list)):
  if list[i][-1] == "last":
    del(list[i+1])
    del(list[i])

I'd like to delete this list where the last item is "last" and the next item on the list. In this example there is a problem every time - I tried different configurations, replacing with numpy array - nothing helps.

Trackback: IndexError: list index out of range

I want the final result of this list to be ['3', '4', 'next']

Give me some tips or help how I can solve it.

Answer 1

Try this:

l = [['2 a', 'nnn', 'xxxx','last'], ['next, next'], ['3', '4', 'next']]
delete_next = False
to_ret = []
for x in l:
    if x[-1] == 'last':
        delete_next = True
    elif delete_next:
        delete_next = False
    else:
        to_ret.append(x)

Using a variable to store if this needs to be deleted