I came across this interesting fact and I am wondering how to come over it. By using inspect it is easy to get the source code of a lambda. But as soon as you return the very same lambda from an eval statement the get source function fails.
import inspect
f = lambda a: a*2
f2 = eval("lambda a: a*2")
inspect.getsource(f), inspect.getsource(f2)
/usr/lib/python3.7/inspect.py in getsource(object)
971 or code object. The source code is returned as a single string. An
972 OSError is raised if the source code cannot be retrieved."""
--> 973 lines, lnum = getsourcelines(object)
974 return ''.join(lines)
975
/usr/lib/python3.7/inspect.py in getsourcelines(object)
953 raised if the source code cannot be retrieved."""
954 object = unwrap(object)
--> 955 lines, lnum = findsource(object)
956
957 if istraceback(object):
/usr/lib/python3.7/inspect.py in findsource(object)
784 lines = linecache.getlines(file)
785 if not lines:
--> 786 raise OSError('could not get source code')
787
788 if ismodule(object):
OSError: could not get source code
Is there a way to come over this and get the source of evaluated code?
Functions don't remember their source code - all they know is the filename and line numbers they came from. If the function definition wasn't in a physical file that is still available, then it is utterly impossible for inspect.getsource() to work. You'd need a decompiler, instead.
thx, jasonharper