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sedrenamefile-renamebatch-renamemv

rename batch files in folder using a textfile

I have a folder of files that start with specific strings and would like to replace part of their strings using the corresponding column from textfile

Folder with files

 ABC_S1_002.txt
 ABC_S1_003.html
 ABC_S1_007.png
 NMC_D1_002.png
 NMC_D2_003.html

And I have a text file that has the strings to be replaced as:

ABC ABC_newfiles
NMC NMC_extra

So the folder after renaming will be 

 ABC_newfiles_S1_002.txt
 ABC_newfiles_S1_003.html
 ABC_newfiles_S1_007.png
 NMC_extra_D1_002.png
 NMC_extra_D2_003.html

I tried file by file using mv 

for f in ABC*; do mv "$f" "${f/ABC/ABC_newfiles}"; done

How can I read in the textfile that has the old strings in first column and replace that with new strings from second column? I tried

IFS=$'\n'; for i in $(cat file_rename);do oldName=$(echo $i | cut -d $'\t' -f1);  newName=$(echo $i | cut -d $'\t' -f2); for f in oldName*; do mv "$f" "${f/oldName/newName}"; done ; done

Did not work though.

Solution

  • Review the result of

    sed -r 's#([^ ]*) (.*)#for f in \1*; do mv "$f" "${f/\1/\2}"; done#' textfile

    When that looks well, you can copy paste the result or wrap it in source:

    source <(sed -r 's#([^ ]*) (.*)#for f in \1*; do mv "$f" "${f/\1/\2}"; done#' textfile)