python: removing all punctuations using string.punctuation EXCEPT a few others

Question

I'm trying to remove punctuations in a string called fs using string.punctuation with the code:

fs = fs.translate({ord(i): None for i in string.punctuation}) 

In the text though, there are several underlines (_)

How do I implement my code such that it ignores underlines and removes all others?

Is it like:

fs = fs.translate({ord(i): None for i in string.punctuation if '_' not in string.punctuation})

Answer 1

string.punctuation is itself just a string, so we could just work with a modified version of the string: {ord(i): None for i in string.punctuation.replace('_', '')}.

The more general technique you are looking for is: the if will be checked separately for each i value, and suppress output (of a key-value pair for the dict) when the check is false. So the condition should not be like ... if '_' not in string.punctuation, but instead simply ... if i != '_'.