I have a problem in which I need to retain the trailing zeros after the mathematical computation.
For eg: 9854.32000 * 1 should return 9854.32000 instead of 9854.32. I tried using
<xsl:decimal-format name="test" decimal-separator="."/>
<xsl:value-of select="format-number(26825.8000 * 1, '#.000', 'test')"/>
But I would like to learn if there is a way for me to do this generically by counting the length of trailing zeros and append them to the result
Please advice
The picture string of format-number()
can be calculated. Consider the following example:
XML
<input>
<multiplicand>1</multiplicand>
<multiplicand>2.0</multiplicand>
<multiplicand>3.14</multiplicand>
<multiplicand>4.000</multiplicand>
<multiplicand>5.0000</multiplicand>
<multiplicand>6.12345</multiplicand>
<multiplicand>7.000000</multiplicand>
</input>
XSLT
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="multiplier" select="2"/>
<xsl:template match="/input">
<output>
<xsl:for-each select="multiplicand">
<xsl:variable name="zeros" select="translate(substring-after(., '.'), '123456789', '000000000')" />
<product>
<xsl:value-of select="format-number(. * $multiplier, concat('#.', $zeros))" />
</product>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<output>
<product>2</product>
<product>4.0</product>
<product>6.28</product>
<product>8.000</product>
<product>10.0000</product>
<product>12.24690</product>
<product>14.000000</product>
</output>