I will provide the code for a portion. It doesn't continue after using commands within a while block. I think it is the code block text = get_audio().lower() that is giving me the error.
def process_text():
pass
if __name__ == "__main__":
assistant_speaks('''Hello, I am a Virtual Assistant.
I am here to make your life easier. You can command me to perform
various tasks such as calculating sums or opening applications.
Please tell me who you are.''')
name = 'are'
name = get_audio()
assistant_speaks("Hello, " + name + '.')
while 1:
assistant_speaks("What can i do for you?" + name + '.')
text = get_audio().lower()
if text == 0:
continue
if "exit" in str(text) or "bye" in str(text) or "sleep" in str(text):
assistant_speaks("Ok bye, " + name + '.')
break
# calling process text to process the query
process_text()
def process_text():
try:
if 'search' in input or 'play' in input:
# a basic web crawler using selenium
search_web(input)
return
elif "who are you" in input or "define yourself" in input:
speak = '''Hello, I am a virtual assistant.
I am here to make your life easier. You can command me to perform
various tasks such as calculating sums or opening applications.'''
assistant_speaks(speak)
return
Basically, it doesn't answer any questions when I ask the elifs. Past the try:
Does anyone have any ideas?
There are at least three mistakes you should correct in order to get the behavior you want from your program:
input
with text
inside the try
block. In Python, input
is a built-in function, not a string. You already assigned the user's answer to the variable text
, so why not use that one? :)process_text
function before you call it. Practically, you should move the line where you call process_text()
somewhere after the definition of that function.process_text()
function: you should un-indent that line back one level, otherwise it will be executed inside the if "exit" in ...
block.You should also define process_text
before the while loop, because you just need to define it once.