Description
I have a small preview picture and when clicking on it, a modal opens with a bigger image.
<a onClick="ToggleImage()" class="toggle-img-btn">
<img class="about-img" src="{{asset("storage/images/about_170.jpg")}}" /></a>
@include('inc.imageModal')
And the image modal:
<div class="img-modal-background" id="img-modal-background">
<div class="img-modal-content">
<input type="checkbox" class="img-close" onClick="ToggleImage()" />
<a class="img-close-cross"></a>
<img class="modal-img" src="{{asset("storage/images/about.jpg")}}">
</div>
</div>
And the JavaScript function for opening/closing the modal:
function ToggleImage() {
const modalBG = document.getElementById("img-modal-background");
const modalIMG = document.querySelector(".modal-img");
if (modalBG.style.display === "flex") {
modalBG.style.opacity = "0";
setTimeout(() => {
modalBG.style.display = "none";
modalIMG.style.display = "none";
}, 500);
} else {
modalBG.style.display = "flex";
modalIMG.style.display = "inherit";
setTimeout(() => {
modalBG.style.opacity = "1";
}, 10);
}
}
Question
I only want to load the image in the modal, when the user opens the modal.
How can i achieve this?
I use Laravel 7 and plain JS.
You can find the repo here
Thanks for your time :)
you can put your image path on js variable and set attribute img src depend modal status like this :
function ToggleImage() {
const modalBG = document.getElementById("img-modal-background");
const modalIMG = document.querySelector(".modal-img");
const img = "storage/images/about.jpg";
if (modalBG.style.display === "flex") {
modalBG.style.opacity = "0";
modalIMG.setAttribute("src", "");
setTimeout(() => {
modalBG.style.display = "none";
modalIMG.style.display = "none";
}, 500);
} else {
modalBG.style.display = "flex";
modalIMG.style.display = "inherit";
modalIMG.setAttribute("src", img);
setTimeout(() => {
modalBG.style.opacity = "1";
}, 10);
}
}