the problem that I am having is that I should read in the values 7 write 0x01 0x27
from my .txt file and the loop will only run 1 time, giving the output 0 - 7 1 0x01 0x27
(the 1 represents write, 0 = read, 2 = not set), but, the values that I have printed out with the print statement show the values as
0 - 7 1 0x30 0x78
1 - 1 2 0x00 0x00 //where the 2 is it reads in 0x27 as a string
So, I am trying to figure out why it is reading in extra values instead of just the ones in the file.
void ioLoad(char* name)
{
std::ifstream inF;
inF.open(name, ios_base::in);
int i = 0;
string rw;
while(!inF.eof()){
inF >> var.time[i]; //int time, from struct 'var'
inF >> rw; //string rw, should read either read or write
inF >> std::hex >> var.address[i] //unsigned char address, from struct 'var' >>PROBLEM LINE<<
if (rw == "write")
{
var.state[i] = WRITE; //stores an enum value as the state
inF >> std::hex >> var.value[i]; //unsigned char value, from struct 'var' >>PROBLEM LINE<<
}
printf("%d - %d %d 0x%02X 0x%02X\n", i, var.time[i], var.state[i], var.address[i], var.value[i]);
i++
}
inF.close()
}
any help would be greatly appreciated and if you need more information please let me know.
var.address[i]
and var.value[i]
have type unsigned char
. Your compiler treats chars as unsigned numerics. So the line inF >> std::hex >> var.address[i]
reads chars. You could understand it just looking at the ASCII table.
When inF >> std::hex >> var.address[i]
performed, the input is 0x01
and '0' is placed to, that is 0x30.
When inF >> std::hex >> var.value[i];
performed, the input is x01
and 'x' is placed to, that is 0x78.
You can read into unsigned int tmp
unsigned tmp;
inF >> std::hex >> tmp;
var.address[i] = static_cast<unsigned char>(tmp);
if (rw == "write") {
var.state[i] = WRITE;
inF >> std::hex >> tmp;
var.value[i] = static_cast<unsigned char>(tmp);
}