I would find the rows in a dataframe which contains all of the elements of a tuple and then set a value in a specific column for the corrisponding index of the row
for ix, row in df.iterrows():
if set(tuple).issubset(row):
df.loc[ix, ['label']] = 1
but I get this error:
TypeError: unhashable type: 'list'
if I perform the following chunk of code it seems that it works but I don't know how to set the value in the label column where the row match the tuple
for row in df.astype(str).values.tolist():
set(tuple).issubset(row))
does anyone have any suggestions?
Thanks for the help
Use enumerate
and iloc
.
for idx, row in enumerate(df.astype(str).values.tolist()):
if set(tuple).issubset(row):
df.iloc[idx, df.columns.get_loc('label')] = 1