I have a regex which works, but unfortunately not in Java because Java does not support this type of inline modifier.
I have already read about this topic e. g. here:
My regex:
(?(?=\d{1,2}[.]\d{1,2}[.]\d{2,4})somerandomtextwhichisnotinthetext|^((($|EUR)? ?[-+]?(\d{1,8}[.,])*\d+([.,]\d+)?)|([-+]?(\d{1,8}[.,])*\d+([.,]\d+)? ?($|€|EUR)?))$)
I also tried a lookbehind but the pattern it should be matched has a variable length an this is unfortunately not supported...
The regex should me matches all of this pattern (a full match is needed --> matcher.group(0) ):
but not this:
And it needs to be implemented in Java.
But still I have no solution...
Thanks for your help!!!
The point here is that you need to use the first part as a negative lookahead to add an exception to the other pattern:
^(?!\d{1,2}[.]\d{1,2}[.]\d{2,4}$)((($|EUR)? ?[-+]?(\d{1,8}[.,])*\d+([.,]\d+)?)|([-+]?(\d{1,8}[.,])*\d+([.,]\d+)? ?($|€|EUR)?))$
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
See the regex demo
So, rather than requiring an exception pattern and then failing to match a fake string, it makes sense to simply use a valid match pattern and add an exception at the start.
I also see ($|€|EUR)?, you probably wanted to match a dollar symbol here. If I am right, replace it with ([$€]|EUR)?. Also, ($|EUR)? might also need replacing with ([$€]|EUR)?.
Also, consider using non-capturing groups rather than capturing ones, since you say you are only interested in full match values.