How to remove spaces between inside a quotation with a regex

Question

I have some text here:

... che si concluse con la " desegregazione " degli autobus.

What regular expression can I use to grab these spaces and turn this into:

... che si concluse con la "desegregazione" degli autobus.

I was thinking of something like (?<=\".{1,20})\" (sorry if it's clunky, I'm a beginner), but apparently Regex doesn't accept quantifiers inside of lookbehinds, so I'm at a loss.

Answer 1

You may use

"\s*([^"]*?)\s*"

Replace with "$1".

See the regex demo

Details

• " - a double quotation mark
• \s* - 0+ whitespaces
• ([^"]*?) - Group 1 ($1 in the replacement pattern refers to this value): any 0+ chars other than " (see [^"] negated character class), as few as possible (see *? non-greedy quantifier)
• \s* - 0+ whitespaces
• " - a double quotation mark.