How to create a file with '01' if name exists?

Question

Is there a specific argument in open() built-in function so that if the filename already exists, it creates a file by adding a number to its name ??

such that if "file.txt" exists, it automatically creates "file-01.txt"

Or any other solution.!

Answer 1

I have found a solution, Thanks!!

b = True
c = 1
while b:
    f_name = 'Task-{:02.0f}.txt'.format(c)
    try:
        f = open(f_name,'x')
        b = False
    except FileExistsError:
        c += 1
f.close()