Is there a specific argument in open() built-in function so that if the filename already exists, it creates a file by adding a number to its name ??
such that if "file.txt" exists, it automatically creates "file-01.txt"
Or any other solution.!
I have found a solution, Thanks!!
b = True
c = 1
while b:
f_name = 'Task-{:02.0f}.txt'.format(c)
try:
f = open(f_name,'x')
b = False
except FileExistsError:
c += 1
f.close()