How to convert CURL command with python requests and retrieve results via API

Question

I'm new to python and encountered problems passing the parameters below that I want to request from the server via API.

I'm using flask as I want this to be web based. Step1: go to index.html and pass teamID teamID = request.form['teamID']. Step2: Authenticate user via API & find data by teamID Step3: Go to the page report.html and display results + save results as CSV file

import subprocess
import json 
import requests
from flask import Flask, render_template, request

#required parameters
myID = 12345 
teamID = 3456
includeSub = 0 
beginDate = "2020-03-20 00:00:00"
endDate = "2020-03-22 00:00:00" 
Type = 1 
authToken = "1245dgfdfg655432gf"
serverURL = https://myurl.com/env/re/

#optional parameters
Category = 1
fpDate = 1
versionP = "1.0"
-----------------

This is CURL command that I would like to convert into python requests format:

#Curl command that i need to covert to python requests format
 "curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'"

my code so far:

app = Flask(__name__)

@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json', 
        'Content-Type': 'application/json', 
        'accessToken': authToken,
        'userID': myID}
commandBody = {
  "teamID": teamID,
  "includeSub": includeSub,
  "beginDate": beginDate,
  "endDate": endDate,
  "Category": Category,
  "fpDate": fpDate,
  "versionP": versionP
}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)

@app.route('/')
def index():
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug=True)

Could someone help with this? So far I tried the code above but received SyntaxError: invalid syntax or TabError: inconsistent use of tabs and spaces in indentation

Thanks in advance!

Answer 1

Thanks to TrillWorks, we have now an online curl to python converter.
So for:

curl -X POST -H \"Content-Type: application/json\" -H \"accessToken:" & authToken & "\" \"" & serverURL & "teamID/" & teamID & "/report\" -d $'" & commandBody & "'

You have:

import requests

headers = {
    '\\Content-Type': 'application/json" -H "accessToken:',
}

response = requests.post('http://&', headers=headers)

It is available HERE.

---

To avoid TabError:

app = Flask(__name__)
@app.route('/reports', methods=['POST'])
def getmyTeamReport(authToken, myID):
teamID = request.form['teamID']
headers = { 'accept': 'application/json', 'Content-Type': 'application/json','accessToken': authToken,'userID': myID}
commandBody = {"teamID": teamID,"includeSub": includeSub,"beginDate": beginDate,"endDate": endDate,"Category": Category,"fpDate": fpDate,"versionP": versionP}
endpoint ='/report'
r = requests.get(serverURL+teamID+endpoint+headers=headers+commandBody=commandBody)
json_object = r.json()
report_t = json_object
return render_template('report.html', report=report_t)
@app.route('/')
def index():
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug=True)