say I've two files test.lua
and m.lua
in a folder, in test.lua
as:
require("m")
then I run this file, howerver it raise an error:
lua: /Users/xx/works/scripts/test.lua:43: module 'm' not found:
no field package.preload['m']
no file '/usr/local/share/lua/5.3/m.lua'
no file '/usr/local/share/lua/5.3/m/init.lua'
no file '/usr/local/lib/lua/5.3/m.lua'
no file '/usr/local/lib/lua/5.3/m/init.lua'
no file './m.lua'
no file './m/init.lua'
no file '/usr/local/lib/lua/5.3/m.so'
no file '/usr/local/lib/lua/5.3/loadall.so'
no file './m.so'
As you can see the line no file './m.lua'
appears but this is not true. ./m.lua
exists, and file permission stuff is OK. If I hardcode the path:
package.path = package.path..';'..'/Users/xx/works/scripts/?.lua'
require('m')
It will work as expected.
What should I do to make lua search current directory fisrt (like python's import) when require a module
The current directory is the directory where you launch lua from.
The command line is missing in your example, if you used lua test.lua
then it shoud work, if you used lua works/scripts/test.lua
then it will not work.