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imagehttpgomultipart

How to send jpeg.Encode image?


I am creating a picture using jpeg.Encode and want to send it. How can I avoid creating an intermediate file?

Create and save file.

  // ...
  outFile, err := os.Create("./images/" + name + ".jpg")
  if err != nil {
    log.Fatal(err)
    os.Exit(-1)
  }
  defer outFile.Close()
  buff := bufio.NewWriter(outFile)

  err = jpeg.Encode(buff, background, &jpeg.Options{Quality: 90})
  if err != nil {
    log.Fatal(err)
    os.Exit(-1)
  }

  err = buff.Flush()
  if err != nil {
    log.Fatal(err)
    os.Exit(-1)
  }

Send file.

  file, err := os.Open("./images/" + name + ".jpg")
  if err != nil {
    log.Fatal(err)
  }

  body := &bytes.Buffer{}
  writer := multipart.NewWriter(body)

  part, err := writer.CreateFormFile("photo", file.Name())
  if err != nil {
    return nil, err
  }

  io.Copy(part, file)
  if err = writer.Close(); err != nil {
    return nil, err
  }

  resp, err := http.Post(uploadURL, writer.FormDataContentType(), body)
  if err != nil {
    return nil, err
  }
  defer resp.Body.Close()

How can I send a photo without saving it on the server?


Solution

  • Simply pass the part target to jpeg.Encode():

    // ...
    
    part, err := writer.CreateFormFile("photo", file.Name())
    if err != nil {
        return nil, err
    }
    
    err = jpeg.Encode(part, background, &jpeg.Options{Quality: 90})
    if err != nil {
        return nil, err
    }
    if err = writer.Close(); err != nil {
        return nil, err
    }
    
    resp, err := http.Post(uploadURL, writer.FormDataContentType(), body)
    if err != nil {
        return nil, err
    }
    defer resp.Body.Close()