Hello i am trying to make a script which takes two arguments (names of directories) and copies the structure of the first into the other.
This is my code:
cd $1 && find . -type d -exec mkdir -p /$2/{} \;
when i run the script i dont get any errors but nothing happens. What am i doing wrong please help thank you.
edit: the script is saved in home and both directories are also in home (~). i run the script in terminal:
sudo bash DN1c.sh dir1 dir2
first directory has multiple subdirectories and the second directory is empty
export src=$1/. dest=$2
find "$src" -type d -exec bash -c 'printf "%s\0" "${@//"$src"/"$dest"}"' sh {} + | xargs -0 mkdir -p