I'm running a program where an exit code of either 0 or 1 indicates success. I'm running this while building a docker image, so if the return code is not 0, the build fails. How can I capture the exit code and force an exit code of 0 if the actual exit code is 0 or 1 so that the docker image can properly build?
I've tried something like this where (exit 1) represents the program:
((exit 1) && if [ $? == 0 || $? == 1]; then exit 0; else exit 1; fi;)
but it's not working, an exit code of 1 still exits with 1.
I would rather not do program || true in case the program actually does fail for some reason
Thanks!
The problem here is that exit 0 has a truthy
value, while exit 1 has a falsy value. This means that the right-part of your condition is only executed when the first part is true (because of the && operator).
If your program exits with code 0, you don't have anything to do. However, what you do want is "transform" a code 1 to a code 0. And to do so, the || operator is what you need.
This should work:
((exit 1) || if [ $? = 1 ]; then exit 0; else exit 1; fi)
A few tests to check (I changed the exit code values to better understand what's happening):
$> ((exit 0) || if [ $? = 1 ]; then exit 2; else exit 3; fi); echo $?
0 # the right-part of the condition is ignored
$> ((exit 1) || if [ $? = 1 ]; then exit 2; else exit 3; fi); echo $?
2 # the exit code 1 is "converted" into an exit code 2 (or 0 in your case)
$> ((exit 2) || if [ $? = 1 ]; then exit 2; else exit 3; fi); echo $?
3 # the exit code 2 is "converted" into an exit code 3 (or 1 in your case)