Hash each line in Text file Python MD5

Question

I'm trying to write a program which will open a text file and give me an md5 hash for each line of text. For example I have a text file with:

66090001081992
66109801042010
68340016052015
68450001062015
79450001062016

This is my code:

import hashlib
hasher = hashlib.md5()
archivo_empleados = open("empleados.txt","rb")
lista = (archivo_empleados.readlines())



archivo_empleados.close()

Answer 1

You could open the file with a with context manager(don't need to call .close()), then iterate each line of the file with a for loop and print the MD5 hash string. You also need to encode in utf-8 before hashing.

import hashlib

def compute_MD5_hash(string, encoding='utf-8'):
    md5_hasher = hashlib.md5()
    md5_hasher.update(string.encode(encoding))
    return md5_hasher.hexdigest()

with open("path/to/file") as f:
    for line in f:
        print(compute_MD5_hash(line))

Which gives hash strings like the following:

58d3ab1af1afd247a90b046d4fefa330
6dea9449f52e07bae45a9c1ed6a03bbc
9e2d8de8f8b3df8a7078b8dc12bb3e35
20819f8084927f700bd58cb8108aabcd
620596810c149a5bc86762d2e1924074

You can have a look at the various hashlib functions in the documentation.