tuple with dict to list with element modification

Question

Given tuple like below,

tpl = ('abc', {'a': 1, 'b': 2})

need to create a list out of this preferably through comprehension if possible.

Expected output

['abc', 'a: 1', 'b: 2']

Tuple can be converted to a list by calling list(tpl)

The part where the dict key:val is converted to key + " : " + val can be done by something like below

[k + " : " + v for k, v in dict.items()]

I think the part of selectively calling the above manipulation be done by checking the type (only for dict) - need some help to get to the complete solution.

Also as a separate problem, is there a way to do this inplace ?

Answer 1

A solution using list-comprehension.

tpl = ('abc', {'a': 1, 'b': 2})
answer = [
  x for dict_or_str in tpl for x in 
  ( 
    [f"{k}: {v}" for k, v in dict_or_str.items()] 
    if isinstance(dict_or_str, dict)
    else [dict_or_str]
  )
]
print(answer)

Output

['abc', 'a: 1', 'b: 2']