How to get generic simple class name from scala TypeTag?

Question

How can I get the simple class name including generic using TypeTag? I think that the method signature should be like:

def getClassName[A: TypeTag](a: A): String

getClassName(Map("a" -> 123)) should return Map[String,Int].

---

Things I've tried:

def getClassName[A: TypeTag](a: A): String = {
  typeOf[A].typeSymbol.name.toString
}

scala> getClassName(Map("a" -> 123))
res1: String = Map

def getClassName[A: TypeTag](a: A): String = {
  typeOf[A].typeSymbol.toString
}

scala> getClassName(Map("a" -> 123))
res1: String = trait Map

def getClassName[A: TypeTag](a: A): String = {
  typeOf[A].toString
}

scala> getClassName(Map("a" -> 123))
res1: String = scala.collection.immutable.Map[String,Int] // It knows the full type!

def getClassName[A: TypeTag](a: A): String = {
  typeOf[A].typeSymbol.fullName
}

scala> getClassName(Map("a" -> 123))
res1: String = scala.collection.immutable.Map

Answer 1

From here: https://docs.scala-lang.org/overviews/reflection/typetags-manifests.html

import scala.reflect.runtime.universe._

def getClassName[T](x: T)(implicit tag: TypeTag[T]): String = {
    tag.tpe match { case TypeRef(_, t, args) => s"""${t.name} [${args.mkString(",")}]""" }
}

getClassName(Map("a" -> 123))

res5: String = Map [java.lang.String,Int]

UPDATE: Shorter version with full class names

 def getClassName[T: TypeTag](x: T) = typeOf[T].toString

getClassName(Map("a" -> 123))
res1: String = scala.collection.immutable.Map[java.lang.String,Int]