I get my Icons in XAML-format, like this (path shortened for better readability):
<DrawingImage x:Key="IcoNew">
<DrawingImage.Drawing>
<DrawingGroup>
<DrawingGroup.Children>
<DrawingGroup>
<DrawingGroup.Children>
<GeometryDrawing Brush="{StaticResource WarningForeground}" Pen="{x:Null}">
<GeometryDrawing.Geometry>
<PathGeometry FillRule="Nonzero" Figures="M20,4L4,4C2.895,4,2,4.895,........" />
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingGroup.Children>
<DrawingGroup.ClipGeometry>
<RectangleGeometry Rect="0,0,24,24" />
</DrawingGroup.ClipGeometry>
</DrawingGroup>
</DrawingGroup.Children>
</DrawingGroup>
</DrawingImage.Drawing>
</DrawingImage>
Then I extract the Pathgeometry and put it into a path-style:
<Style x:Key="IcoNew" TargetType="{x:Type Path}">
<Setter Property="Stretch" Value="Uniform"/>
<Setter Property="Fill" Value="{StaticResource MainAccentColor}"/>
<Setter Property="Data">
<Setter.Value>
<PathGeometry FillRule="Nonzero" Figures="M20,4L4,4C2.895,4,2,4.895,........" />
</Setter.Value>
</Setter>
</Style>
Then I can Inject any of my Icons into a Button-content (and also its color), like this:
<Button.Template>
<ControlTemplate>
<Grid Height="{Binding Path=MaxWidth, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}" Width="{Binding Path=MaxWidth, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}">
<Path Name="vbx" Fill="{Binding Path=Foreground, TargetNullValue={StaticResource SidebarIconColor}, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}"
Height="{Binding Path=MinWidth, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}"
Width="{Binding Path=MinWidth, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}"
Style="{Binding Path=Content, RelativeSource={RelativeSource FindAncestor,AncestorType={x:Type Button}}}"/>
</Grid>
</ControlTemplate>
</Button.Template>
That works really well, even though I lose the RectangleGeometry. My problem is that this only works with Icons that have only 1 PathGeometry included. I don't know how to convert it if I have a XAML Icon like this with multiple paths that also depend on the rectanglegeometry:
<DrawingImage x:Key="Icons8_Attach_11321">
<DrawingImage.Drawing>
<DrawingGroup>
<DrawingGroup.Children>
<DrawingGroup>
<DrawingGroup.Children>
<GeometryDrawing Brush="{x:Null}">
<GeometryDrawing.Pen>
<Pen Brush="#FFFFFFFF" Thickness="2" />
</GeometryDrawing.Pen>
<GeometryDrawing.Geometry>
<PathGeometry FillRule="Nonzero" Figures="M14.742,28.793C13.184,30.352 13.184,32.878 14.742,34.436 16.3,35.995 18.826,35.995 20.384,34.436L35.488,19.332" />
</GeometryDrawing.Geometry>
</GeometryDrawing>
<GeometryDrawing Brush="{x:Null}">
<GeometryDrawing.Pen>
<Pen Brush="#FFFFFFFF" Thickness="2" />
</GeometryDrawing.Pen>
<GeometryDrawing.Geometry>
<PathGeometry FillRule="Nonzero" Figures="M27.025,10.869L7.336,30.557C4.221,33.672 4.221,38.727 7.337,41.842 10.453,44.957 15.506,44.957 18.621,41.842L43.248,17.216C45.584,14.88 45.584,11.09 43.248,8.753 40.91,6.415 37.119,6.416 34.783,8.753L14.742,28.793" />
</GeometryDrawing.Geometry>
</GeometryDrawing>
</DrawingGroup.Children>
<DrawingGroup.ClipGeometry>
<RectangleGeometry Rect="0,0,50,50" />
</DrawingGroup.ClipGeometry>
</DrawingGroup>
</DrawingGroup.Children>
</DrawingGroup>
</DrawingImage.Drawing>
</DrawingImage>
any Ideas how I can get multiple Pathgeometrys + the RectangelGeometry as a Style into my button?
You can use a GeometryGroup
:
<Setter Property="Data">
<Setter.Value>
<GeometryGroup>
<PathGeometry FillRule="Nonzero" Figures="M14.742,28.793C13.184,30.352 13.184,32.878 14.742,34.436 16.3,35.995 18.826,35.995 20.384,34.436L35.488,19.332" />
<PathGeometry FillRule="Nonzero" Figures="M27.025,10.869L7.336,30.557C4.221,33.672 4.221,38.727 7.337,41.842 10.453,44.957 15.506,44.957 18.621,41.842L43.248,17.216C45.584,14.88 45.584,11.09 43.248,8.753 40.91,6.415 37.119,6.416 34.783,8.753L14.742,28.793" />
</GeometryGroup>
</Setter.Value>
</Setter>
(I had to use Stroke
instead of Fill
though for the icon to be displayed correctly.)