Say I have two numbers, a
and b
such that
1 <= a, b <= 10**9
How can I quickly check which is greater: a^b
or b^a
? Calculating a**b
directly in Python is too slow.
This is more of a mathematical question than a Python related question, but you can use math.log
to find the b * math.log(a)
and a * math.log(b)
and compare them.
import math
a = 10
b = 9
if b * math.log(a) > a * math.log(b):
print("a^b is greater than b^a")
else if b * math.log(a)< a * math.log(b):
print("a^b is smaller than b^a")