How to describe the inherited class?

Question

I have one Base and many (1..N) Derived classes like that:

class Base {
public:
  virtual void OnMouseMove(int x, int y) = 0;
}

class Derived_1: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

class Derived_2: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

void Derived_1::OnMouseMove(int x, int y) {actions 1};
void Derived_2::OnMouseMove(int x, int y) {actions 2};

All derived classes have the same definition but different OnMouseMove() functions. I do not like how the program looks, because I have to write in header files all the same derived functions only with different names Derived_1, Derived_2.

Is it possible to write program shorter? I need something like that:

class Derived: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

class Derived_1 : public Derived{};
class Derived_2 : public Derived{};

void Derived_1::OnMouseMove(int x, int y) {actions 1};
void Derived_2::OnMouseMove(int x, int y) {actions 1};

Answer 1

What about using templates in that case like this one:

class Base {
public:
  virtual void OnMouseMove(int x, int y) = 0;
};  

template < int N>
class Derived: public Base {
public:
  void OnMouseMove(int x, int y) override;
};

template<> void Derived<1>::OnMouseMove(int x, int y) {std::cout<< "1"<< std::endl;}
template<> void Derived<2>::OnMouseMove(int x, int y) {std::cout<< "2"<< std::endl;}

int main()
{
    Base* ptr1 = new Derived<1>;
    Base* ptr2 = new Derived<2>;

    ptr1->OnMouseMove(5,6);
    ptr2->OnMouseMove(5,6);
}