getting first part of a string that has two parts

Question

I have a string that has two parts (path and owner) both separated by a space.

This is the input file input.txt

/dir1/dir2/file1 @owner1
/dir1/dir2/foo\ bar @owner2

I want to extract all the paths to a separate output file - output.txt I cannot use space as delimiter since paths can also have filenames with space and delimiter in them

/dir1/dir2/file1
/dir1/dir2/foo\ bar

Answer 1

Here could be a different way of doing it with rev + GNU grep:

rev file | grep -oP '.*@ \K.*' | rev

OR

rev file | grep -oP '.*@\s+\K.*' | rev

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With original simple solution go with:

awk -F' @' '{print $1}' Input_file