Search code examples
windows-vistabatch-filecommand-prompt

How to properly set the path in Windows Vista cmd using batch file?

I am a complete newbie when it comes to programming and some basic computer concepts so pls be patient with me if my question might look so silly.

I am trying to create a batch file command that will automatically redirect me to a particular directory. What happens is that when I call the batch file it will only display the path but still in the same directory. I am doing this for shortcut purposes.

This is the default directory whenever I open my cmd-prompt (I don't want to change the default):

C:\Users\eacomm>


Here's the command that I typed and saved it as setpath.bat:

path=C:\Program Files\EasyPHP-5.3.6.0\www\cakephp;


Here is the result whenever I call setpath and hit ENTER:

C:\Users\eacomm>C:\Program Files\EasyPHP-5.3.6.0\www\cakephp;


I want to redirect this one... Whats wrong with this??? Pls help...

Solution

  • Why don't use simply:

    cd C:\Program Files\EasyPHP-5.3.6.0\www\cakephp

    inside your .bat file?