ValueError: invalid literal for int() in my program and if statement inside a except

Question

I have a program that takes input and adds it to a list and spits out the average of said list. I want to make it so you can type MENU and it will stop the programy() and let you either exit or restart the programy(). Everything works fine until you type MENU (all caps). Thank you everyone! :) Still new to python.

from functools import reduce

def programy():
    running = True

    print("I output the average of a list that you add files to.")
    listy = []

    while running == True:
        def listaverage(givenlist):
            print(sum(listy) / len(listy))

        currentnum = input("Please type a number to add to the list: ")

        try:
            val = int(currentnum)
        except ValueError:
            if str(currentnum) == "MENU":
                running = False
            else:
                print("Not a number!")
                continue

        listy.append(int(currentnum))
        listaverage(listy)

    answer = input("Please type either: EXIT or RESTART")

    if str(answer) == "RESTART":
        running = True
    if answer == "EXIT":
        exit

programy()

Traceback (most recent call last):
  File "C:\Users\hullb\OneDrive\Desktop\average_via_input.py", line 34, in <module>
    programy()
  File "C:\Users\hullb\OneDrive\Desktop\average_via_input.py", line 24, in programy
    listy.append(int(currentnum))
ValueError: invalid literal for int() with base 10: 'MENU

Answer 1

if str(currentnum) == "MENU":
    running = False

sets the while condition to false and stops the next iteration from running, but the current one hasn't ended yet, so in int(currentnum) you are trying to convert "MENU" to int.

Use isdigit() instead to check the value

if currentnum.isdigit():
    listy.append(int(currentnum))
    listaverage(listy)
else:
    if str(currentnum) == "MENU":
        running = False
    else:
        print("Not a number!")