We have a transactional table with ORC file format and ZLiB compression. It's an internal table. When reading through Hive CLI I can read the table. But when runnnig select through spark sql it shows table with all the columns and 0 rows. Please help.
This can also be achieved using Pyspark but you have to add a few configurations to it, below is the code sample to do the same in Pyspark
from pyspark.sql import *
from pyspark_llap import HiveWarehouseSession
from pyspark.sql import SparkSession
from pyspark.sql.rdd.RDD
from pyspark.sql.types import *
from pyspark.sql import Window
from pyspark.sql.functions import *
from pyspark.sql.functions import *
spark = SparkSession.builder \
.appName("appname") \
.enableHiveSupport() \
.getOrCreate()
hive = HiveWarehouseSession.session(spark).build()
sample = hive.executeQuery("""select * from <schema.tablename>""")
sample.show()`
to execute the above using spark-submit add the configuration as below
spark-submit --jars /usr/hdp/3.1.0.0-78/hive_warehouse_connector/hive-warehouse-connector-assembly-1.0.0.3.1.0.0-78.jar --py-files /usr/hdp/current/hive_warehouse_connector/pyspark_hwc-1.0.0.3.1.0.0-78.zip --conf spark.sql.hive.hiveserver2.jdbc.url="jdbc URL;serviceDiscoveryMode=zooKeeperHA;zooKeeperNamespace=hs2ActivePassiveHA" --conf spark.hadoop.hive.llap.daemon.service.hosts="@llap0" --conf spark.datasource.hive.warehouse.load.staging.dir="/tmp" --conf spark.hadoop.hive.zookeeper.quorum="all zookeeper urls" --conf spark.sql.hive.hiveserver2.jdbc.url.principal="url for JDBC connection" --conf spark.security.credentials.hiveserver2.enabled="true" TestPysparkJob.py