Exclude multiple keys from glob array PHP

Question

I am new to php and i am trying to make a dinamic menu ( if i add a php file to the directory to be automaticaly added to the menu) my issue is that i want to exclude 3 specific pages from there like app.php, mdx.php and script.php this is the code i am using to get the menu up and running :

<?php
$dir = ".";
$htmlFiles = glob("$dir/*.{html,htm,php}", GLOB_BRACE);

// Sort in ascending order - this is default
echo '<ul>';
foreach($htmlFiles as $htmlFile)
{
  echo '<li><a href="'.basename($htmlFile).'">'.mb_strtoupper(basename($htmlFile,".php")).'</a></li>';

}
echo '</ul>';

?>

How do i do that ?

Answer 1

Maybe something like that?

<?php
$dir = ".";
$cutFiles = ['app.php', 'mdx.php','script.php']; //file You don't want 
$htmlFiles = glob("$dir/*.{html,htm,php}", GLOB_BRACE);

$htmlFiles = array_diff($html_Files, $cutFiles); //computed differences

// Sort in ascending order - this is default
echo '<ul>';
foreach($htmlFiles as $htmlFile)
{
  echo '<li><a href="'.basename($htmlFile).'">'.mb_strtoupper(basename($htmlFile,".php")).'</a></li>';

}
echo '</ul>';

?>